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gfsub

Subtract polynomials over a Galois field

Syntax

Description

c = gfsub(a,b,p) calculates a minus b, where a and b represent polynomials over GF(p) and p is a prime number. a, b, and c are row vectors that give the coefficients of the corresponding polynomials in order of ascending powers. Each coefficient is between 0 and p-1. If a and b are matrices of the same size, then the function treats each row independently.

c = gfsub(a,b,p,len) subtracts row vectors as in the syntax above, except that it returns a row vector of length len. The output c is a truncated or extended representation of the answer. If the row vector corresponding to the answer has fewer than len entries (including zeros), then extra zeros are added at the end; if it has more than len entries, then entries from the end are removed.

c = gfsub(a,b,field) calculates a minus b, where a and b are the exponential format of two elements of GF(pm), relative to some primitive element of GF(pm). p is a prime number and m is a positive integer. field is the matrix listing all elements of GF(pm), arranged relative to the same primitive element. c is the exponential format of the answer, relative to the same primitive element. See Representing Elements of Galois Fields for an explanation of these formats. If a and b are matrices of the same size, then the function treats each element independently.

Examples

In the code below, differ is the difference of 2 + 3x + x2 and 4 + 2x + 3x2 over GF(5), and linpart is the degree-one part of differ.

The code below shows that , where A is a root of the primitive polynomial 2 + 2x + x2 for GF(9).

See Also
gfadd, gfconv, gfmul, gfdeconv, gfdiv, gftuple


  gfroots gftable