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Approximation Space
We seek an approximate solution by collocation from
piecewise cubics with a suitable break sequence; for instance,
Since cubics are of order 4, we have
and since
requires two smoothness conditions across each interior break, we want knot multiplicity = 4-2 = 2, hence use the knot sequence
which we could also have obtained as knots = augknt(breaks,4,2). This gives a quadruple knot at both 0 and 1, which is consistent with the fact that we have cubics, i.e., have order 4.
| Problem | Discretization | ![]() |